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3x^2-5x-372=0
a = 3; b = -5; c = -372;
Δ = b2-4ac
Δ = -52-4·3·(-372)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-67}{2*3}=\frac{-62}{6} =-10+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+67}{2*3}=\frac{72}{6} =12 $
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